0322重写代码：

#include<algorithm>
#include<iostream>
using namespace std;

int maxx=1000000010,minn=-1;

int main()
{
    int n;
    scanf("%d",&n);
    for(int i=0;i<n;i++){
        int a,b;
        scanf("%d%d",&a,&b);
        maxx = min(maxx,a/b);
        minn = max(minn,a/(b+1)+1);
    }
    printf("%d %d\n",minn,maxx);
    return 0;
}

​​​​​​​

二分代码1：

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;

int get(int a, int b){
	int l=1;r=1e9+1;
	while(l<r){
		int mid = l+r >>1;
		if(a / mid <= b){
			r = mid;
		}
		else l = mid + 1;
	}
	return l;
} 

int main()
{
	int n;
	scanf("%d",&n);
	int minn = 1,maxx = 1e9;
	while(n--){
		int a,b;
		scanf("%d%d",&a,&b);
		minn = max(minn,get(a,b));
		maxx = min(maxx,get(a,b-1) - 1);
	}
	cout<<minn<<" "<<maxx<<endl;
	return 0;
}

误打误撞代码2：

#include<iostream>
#include<cstdio>
#include<cmath>
using namespace std;
int n;

//设最小是minn,最大是maxx,最大的情况就是除，一个也没浪费 
 int v[10010];
 int x[10010];
 int minn = -1;
 int maxx = 1000000000;
int main()
{
	scanf("%d",&n);
	for(int i = 0;i < n; i ++){
		scanf("%d%d",&v[i],&x[i]);
		maxx = min(v[i]/x[i], maxx); 
		minn = max(v[i]/(x[i]+1)+1, minn);
	}
	
	//cout<<xx<<" "<<vv<<endl; 
	cout<<minn<<" "<<maxx<<endl;
	return 0;
}