//用switch...case语句统计数字、空格和其他字符出现的次数

//转自K&R

#include

int main(void)

{

int c, i, nwhite, nother, ndigit[10];

nwhite = nother = 0;

for (i = 0; i < 10; i++)

ndigit[i] = 0;

while ((c = getchar()) != EOF)

{

switch (c)

{

case '0': case '1': case '2': case '3': case '4':

case '5': case '6': case '7': case '8': case '9':

ndigit[c-'0']++;

break;

case ' ':

case '\n':

case '\t':

nwhite++;

break;

default:

nother++;

break;

}

}

printf("digits =");

for (i = 0; i < 10; i++)

printf(" %d", ndigit[i]);

printf(", white space = %d, other = %d\n",nwhite, nother);

return 0;

}