1. 写一个匿名函数，判断指定的年是否是闰年 (先直接用普通函数)

   def fun1(year):
       if year%100!=0 and year%4==0 or year%400==0:
           return f'{year}年是闰年'
   print(fun1(2000))
   #2000年是闰年
   

2. 写一个函数将一个指定的列表中的元素逆序( 如[1, 2, 3] -> [3, 2, 1])(注意:不要使用列表自带的逆序函数)

   def fun2(list1:list):
       return list1[-1:-(len(list1))-1:-1]
   print(fun2([1, 2, 3]))
   

3. 编写一个函数，计算一个整数的各位数的平方和

例如: sum1(12) -> 5（1的平方加上2的平方）    sum1(123) -> 14
def fun3(num):
    result=0
    for i in str(num):
        result+=int(i)**2
    return result
print(fun3(12))

4. 求列表 nums 中绝对值最小的元素

例如：nums = [-23, 100, 89, -56, -234, 123], 绝对值最小的元素是：-23
def fun4(list1:list):
    minnum = list1[0]
    for i in list1:
        if i>=0 and i<minnum:
            minnum = i
        elif i<0 and -(i)<minnum:
            minnum = i
    return minnum
print(fun4([-23, 100, 89, -56, -234, 123]))

5. 已经两个列表A和B，用map函数创建一个字典，A中的元素是key，B中的元素是value

A = ['name', 'age', 'sex']
B = ['张三', 18, '女']
新字典: {'name': '张三', 'age': 18, 'sex': '女'}
#map高级函数
def fun5_1(key,value):
    return key,value
A = ['name', 'age', 'sex']
B = ['张三', 18, '女']
print(dict(map(fun5_1, A, B)))

#一般方法
def fun5(A:list,B:list):
    newlist=[]
    for i in range(len(A)):
        key = A[i]
        value = B[i]
        newlist.append([key,value])
    return dict(newlist)
A = ['name', 'age', 'sex']
B = ['张三', 18, '女']
print(fun5(A, B))

6. 已经三个列表分别表示5个学生的姓名、学科和班号，使用map将这个三个列表拼成一个表示每个学生班级信息的的字典

   names = ['小明', '小花', '小红', '老王']
   nums = ['1906', '1807', '2001', '2004']
   subjects = ['python', 'h5', 'java', 'python']
   结果：{'小明': 'python1906', '小花': 'h51807', '小红': 'java2001', '老王': 'python2004'}
   
   def fun6(x,y,z):
       return x,y+z
   names = ['小明', '小花', '小红', '老王']
   nums = ['1906', '1807', '2001', '2004']
   subjects = ['python', 'h5', 'java', 'python']
   print(dict(map(fun6,names,subjects,nums)))
   

7. 已经一个列表message, 使用reduce计算列表中所有数字的和

   message = ['你好', 20, '30', 5, 6.89, 'hello']
   结果：31.89
   #普通方法
   def fun7(list1:list):
       total = 0
       for x in list1:
           if type(x) == int or type(x) == float:
               total += x
       return total
   message = ['你好', 20, '30', 5, 6.89, 'hello']
   print(fun7(message))
   
   
   #使用reduce高级函数
   from functools import reduce
   def fun(x,y):
       return x+y
   message = ['你好', 20, '30', 5, 6.89, 'hello']
   newmessage = [i for i in message if type(i) == int or type(i) == float]
   print(reduce(fun, newmessage))
   

8. 已经列表points中保存的是每个点的坐标(坐标是用元组表示的，第一个值是x坐标，第二个值是y坐标）

   points = [
     (10, 20), (0, 100), (20, 30), (-10, 20), (30, -100)
   ]
   

   1）获取列表中y坐标最大的点

   def fun8_2(list1:list):
       maxnum = list1[0][0]
       for value in list1:
               if value[1]>maxnum:
                   maxnum = value[1]
       return maxnum
   points = [
     (10, 20), (0, 100), (20, 30), (-10, 20), (30, -100)
   ]
   print(fun8_2(points))  #100
   

   2）获取列表中x坐标最小的点

   def fun8_2(list1:list):
       minnum = list1[0][0]
       for value in list1:
               if value[0]<minnum:
                   minnum = value[0]
       return minnum
   points = [
     (10, 20), (0, 100), (20, 30), (-10, 20), (30, -100)
   ]
   print(fun8_2(points))  #-10
   

   3）获取列表中距离原点最远的点

   def fun8_3(list1:list):
       maxnum = list1[0][1]**2+list1[0][0]**2
       for value in list1:
           if value[0]**2+value[1]**2>maxnum:
               maxnum = value[0]**2+value[1]**2
               maxpoint = value
       return maxpoint
   points = [
     (10, 20), (0, 100), (20, 30), (-10, 20), (30, -100)
   ]
   print(fun8_3(points))  #(30, -100)
   

   4）将点按照点到x轴的距离大小从大到小排序

   def fun8_4(list1:list):
       for j in range(len(list1)):
           for i in range(len(list1)-1-j):
               if list1[i][0]<list1[i+1][0]:
                   list1[i+1],list1[i] = list1[i],list1[i+1]
       return list1
   points = [
     (10, 20), (0, 100), (20, 30), (-10, 20), (30, -100)
   ]
   print(fun8_4(points))
   #[(30, -100), (20, 30), (10, 20), (0, 100), (-10, 20)]