#求100以内的素数并输出
def isPrime(num):for i in range(2,num):if num%i == 0:return Falsereturn True
sum = 2#1不是素数，2是素数#对[3,100)内的整数逐一进行判断
for i in range(3,100):if isPrime(i):sum += iprint(sum)
优化版：
from math import sqrti = 2
while i <= 100:j = 2while j <= sqrt(i):if i%j == 0:breakj += 1 if j > sqrt(i):print(i,end = ' ')i += 1
from math import sqrtfor i in range(2,101):k = int(sqrt(i))flag = 1for j in range(2,k+1):if i%j == 0:flag = 0breakif(flag):print(i,end = " ")
